携手创作，共同成长！这是我参与「掘金日新计划 · 8 月更文挑战」的第21天，www.kaggle.com/competition…

Find ships on satellite images as quickly as possible

Data Description

In this competition, you are required to locate ships in images, and put an aligned bounding box segment around the ships you locate. Many images do not contain ships, and those that do may contain multiple ships. Ships within and across images may differ in size (sometimes significantly) and be located in open sea, at docks, marinas, etc.

For this metric, object segments cannot overlap. There were a small percentage of images in both the Train and Test set that had slight overlap of object segments when ships were directly next to each other. Any segments overlaps were removed by setting them to background (i.e., non-ship) encoding. Therefore, some images have a ground truth may be an aligned bounding box with some pixels removed from an edge of the segment. These small adjustments will have a minimal impact on scoring, since the scoring evaluates over increasing overlap thresholds.

The train_ship_segmentations.csv file provides the ground truth (in run-length encoding format) for the training images. The sample_submission files contains the images in the test images.

Please click on each file / folder in the Data Sources section to get more information about the files.

kaggle competitions download -c airbus-ship-detection

2.数据展示

2.1 标注数据

该数据以csv格式存储，具体如下：

2.2 图象文件

3.格式转换

由于图太多，暂时转换10个

#!/usr/bin/env python3
# -*- coding: utf-8 -*-

import numpy as np  # linear algebra
import pandas as pd  # data processing, CSV file I/O (e.g. pd.read_csv)
from PIL import Image


# ref: https://www.kaggle.com/paulorzp/run-length-encode-and-decode
# 将图片编码成rle格式
def rle_encode(img, min_max_threshold=1e-3, max_mean_threshold=None):
    '''
    img: numpy array, 1 - mask, 0 - background
    Returns run length as string formated
    '''
    if np.max(img) < min_max_threshold:
        return ''  ## no need to encode if it's all zeros
    if max_mean_threshold and np.mean(img) > max_mean_threshold:
        return ''  ## ignore overfilled mask
    pixels = img.T.flatten()
    pixels = np.concatenate([[0], pixels, [0]])
    runs = np.where(pixels[1:] != pixels[:-1])[0] + 1
    runs[1::2] -= runs[::2]
    return ' '.join(str(x) for x in runs)


# 将图片从rle解码
def rle_decode(mask_rle, shape=(768, 768)):
    '''
    mask_rle: run-length as string formated (start length)
    shape: (height,width) of array to return
    Returns numpy array, 1 - mask, 0 - background
    '''
    s = mask_rle.split()
    starts, lengths = [np.asarray(x, dtype=int) for x in (s[0:][::2], s[1:][::2])]
    starts -= 1
    ends = starts + lengths
    img = np.zeros(shape[0] * shape[1], dtype=np.uint8)
    for lo, hi in zip(starts, ends):
        # img[lo:hi] = 1
        img[lo:hi] = 255 #方便可视化
    return img.reshape(shape).T  # Needed to align to RLE direction


def masks_as_image(in_mask_list):
    # Take the individual ship masks and create a single mask array for all ships
    all_masks = np.zeros((768, 768), dtype=np.uint8)
    for mask in in_mask_list:
        if isinstance(mask, str):
            all_masks |= rle_decode(mask)
    return all_masks


# 将目标路径下的rle文件中所包含的所有rle编码，保存到save_img_dir中去
def rle_2_img(train_rle_dir, save_img_dir):
    masks = pd.read_csv(train_rle_dir)
    not_empty = pd.notna(masks.EncodedPixels)
    print(not_empty.sum(), 'masks in', masks[not_empty].ImageId.nunique(), 'images')
    print((~not_empty).sum(), 'empty images in', masks.ImageId.nunique(), 'total images')
    all_batchs = list(masks.groupby('ImageId'))
    train_images = []
    train_masks = []
    i = 0
    for img_id, mask in all_batchs[:10]:
        c_mask = masks_as_image(mask['EncodedPixels'].values)
        im = Image.fromarray(c_mask)
        im.save(save_img_dir + img_id.split('.')[0] + '.png')
        print(i, img_id.split('.')[0] + '.png')
        i += 1

    return train_images, train_masks


if __name__ == '__main__':
    rle_2_img('train_ship_segmentations_v2.csv',
              'mask/')

其中为了方便查看，原计划0为背景，1为mask，为了方便显示，设置为255为mask。

3.转换结果